CuO+H₂ → Cu +H₂O redox equation

Cu   H₂O

Explanation:

CuO + H₂  > Cu + H₂O

Oxidation : Gaining of oxygen OR Losing of hydrogen

Reduction : Gaining of Hydrogen OR Losing of Oxygen

Here ,

CuO gets reduced [ it loses oxygen ] and become Cu

H₂ gets oxidized  [ it gains oxygen ] and becomes H₂O

Substance that gets oxidised = H₂

Substance that gets reduced = CuO

Also ,

Oxidising agent = substance that gets reduced = CuO

Reducing agent = substance that gets oxidized = H₂

the answer is 303.15 or 303

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.