If 28 grams of N reacts completely with 12 grams of H2, then how many grams of NH6 will you end up with? grams

40 Grams

Explanation:

add the 28 and 12 NH6 and H2 doesn't matter for the grams because they are way way less then grams in weight

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm