When 100.0 mL of 1.000 M HCl is reacted with 100.0 mL of 1.000 M NH4OH, the solution’s temperature increases 7.01 °C. Calculate LaTeX: \DeltaΔHreaction in units of kJ/mol. The specific heat of the salt solution is 4.184 J/g-°C and the density is 1.010 g/mL. Do not use units or labels in answer. Make sure answer has the correct sig figs.

Explanation:

volume of solution = 100 + 100 = 200 mL

mass of reaction mixture = 200 x 1.010 = 202 g

specific heat of solution mixture = 4.184 J/g-°C

heat evolved = mass x specific heat x rise in temperature

= 202 x 4.184 x 7.01

= 5924.63 J

100 mL of 1 M HCl

= .1 L of 1M HCl will contain .1 mole of HCl

.1 mole reacts with .1 mole of NH₄OH to make 5924.63 J of heat

1 mole reacts with 1 mole of NH₄OH to make 59246.3 J of heat

heat of reaction = 59246.3 J / mol

= 59.246 kJ / mol

= 59.3 kJ / mol .

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.