A cylinder containing 5.20 L of NO gas at 1.20 atm and 32 o C is compressed under 6.00 atm pressure to a volume of 2.08 L. What is the final temperature of the gas?

337 °C

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 5.20 L

Initial pressure (P1) = 1.20 atm

Initial temperature (T1) = 32 °C

Final pressure (P2) = 6 atm

Final volume (V2) = 2.08 L

Final temperature (T2) =?

Next, we shall convert 32 °C to Kelvin temperature. This can be obtained as follow:

T (K) = T (°C) + 273

Initial temperature (T1) = 32 °C

Initial temperature (T1) = 32 °C + 273

Initial temperature (T1) = 307 K

Next, we shall determine the final temperature of the gas as illustrated below:

Initial volume (V1) = 5.20 L

Initial pressure (P1) = 1.20 atm

Initial temperature (T1) = 305 K

Final pressure (P2) = 6 atm

Final volume (V2) = 2.08 L

Final temperature (T2) =?

P1V1 /T1 = P2V2 /T2

1.2 × 5.2 / 305 = 6 × 2.08 / T2

Cross multiply

1.2 × 5.2 × T2 = 305 × 6 × 2.08

6.24 × T2 = 3806.7

Divide both side by 6.24

T2 = 3806.7 / 6.24

T2 = 610 K

Finally, we shall convert 610 K to celsius temperature. This can be obtained as follow:

T (°C) = T(K) – 273

T(K) = 610 K

T (°C) = 610 – 273

T (°C) = 337 °C

Thus, the final temperature of the gas is 337 °C.

c)red bank

explanation:

red bank is a borough in monmouth county, new jersey, incorporated in 1908 and located on the navesink river, the area's original transportation route to the ocean and other ports.

the product of the pressure and volume is also constant