In an aqueous solution, a 0.100 M solution of glucose is prepared with a total volume of 0.150 Liters. If the molar mass of glucose is 180.16 g/mol how many grams must the solution contain?

2.70 g of glucose.

Explanation:

The following data were obtained from the question:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Next, we shall determine the number of mole of glucose in the solution. This can be obtained as follow:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Mole glucose =?

Molarity = mole /Volume

0.1 = Mole of glucose /0.15

Cross multiply

Mole of glucose = 0.1 × 0.15

Mole of glucose = 0.015 mole

Finally, we shall determine the mass of glucose in the solution as follow:

Mole of glucose = 0.015 mole

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Mole = mass /molar mass

0.015 = mass of glucose /180.16

Cross multiply

Mass of glucose = 0.015 × 180.16

Mass of glucose = 2.70 g

Therefore, the solution contains 2.70 g of glucose.

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