Calculate the energy required to heat 622 g mercury from 37°C to 42°C. The specific
heat capacity of Hg(l) is 0.138 J/g.° C.
Answer in units of cal.

102.58 cal.

Explanation:

Given data:

Mass of mercury = 622 g

Initial temperature = 37°C

Final temperature = 42°C

Specific heat capacity of mercury = 0.138 J/g.°C

Energy required = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 42°C - 37°C

ΔT = 5°C

Q = 622 g × 0.138 J/g.°C × 5°C

Q = 429.18 J

J to cal:

429.18 J × 1 cal /4.184 j

102.58 cal.

the answer for sodium is 0.186

the answer for rubidium is 0.251