I'm confused on this question. Could anyone tell me how to go about doing it ASAP. I will give brainliest. One fuel used to power the main engines of rockets is liquid hydrogen. It reacts in the presence of oxygen to produce water in this reaction: H2 + O2 --> H2O
If an rockets main engine can hold 1.44 x 106 grams of hydrogen, how much oxygen would be needed to fully react all of it?
How much water would be produced if all of the hydrogen above reacted?

3.57 × 10⁵ mol O₂

7.13 × 10⁵ mol H₂O

Explanation:

Step 1: Write the balanced equation

2 H₂ + O₂ ⇒ 2 H₂O

Step 2: Calculate the moles corresponding to 1.44 × 10⁶ g of hydrogen

The molar mass of hydrogen is 2.02 g/mol.

1.44 × 10⁶ g × (1 mol/2.02 g) = 7.13 × 10⁵ mol

Step 3: Calculate the moles of oxygen needed to react with 7.13 × 10⁵ moles of hydrogen

The molar ratio of H₂ to O₂ is 2:1. The reacting moles of oxygen are 1/2 × 7.13 × 10⁵ mol = 3.57 × 10⁵ mol.

Step 4: Calculate the moles of water produced from 7.13 × 10⁵ moles of hydrogen

The molar ratio of H₂ to H₂O is 2:2. The moles of water formed are 2/2 × 7.13 × 10⁵ mol = 7.13 × 10⁵ mol.

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.