80 POINTS 1. 14.07g of solid sucrose (C12H22O11) are dissolved in 0.35 L of water. What is the molarity of the solution?

2. What is the molarity of a sucrose solution with a concentration of 4.5 ppm (mg/L)?

3. What is the molarity of the same sucrose solution if you dilute 40 mL of it into a 500 mL volumetric flask?

4. A cosmetic chemist is making a lotion which can have a maximum concentration of 0.04 M glycerol (C3H6O3). If each bottle of lotion is 0.5 liters, how many moles could each bottle have at the maximum?

5. What is the pH of an aqueous solution of the strong acid, Perchloric Acid (HClO4), with a concentration of 0.007 M?

6. In the following reaction, how many moles of HNO3 are needed to react with 7 moles of KOH to achieve a pH of 7.00?

HNO3 + KOH H2O + KNO3

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Explanation:

1. 14.07g of solid sucrose (C12H22O11) are dissolved in 0.35 L of water. What is the molarity of the solution?

2. What is the molarity of a sucrose solution with a concentration of 4.5 ppm (mg/L)?

3. What is the molarity of the same sucrose solution if you dilute 40 mL of it into a 500 mL volumetric flask?

4. A cosmetic chemist is making a lotion which can have a maximum concentration of 0.04 M glycerol (C3H6O3). If each bottle of lotion is 0.5 liters, how many moles could each bottle have at the maximum?

5. What is the pH of an aqueous solution of the strong acid, Perchloric Acid (HClO4), with a concentration of 0.007 M?

6. In the following reaction, how many moles of HNO3 are needed to react with 7 moles of KOH to achieve a pH of 7.00?

HNO3 + KOH H2O + KNO3

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Explanation:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.