A 350 mL air sample collected at 308 K has a pressure of 73 kPa. What will be the pressure of the sample if it is allowed to expand to 425 mL at
333K?

65 kPa

Explanation:

Step 1: Given data

Initial pressure (P₁): 73 kPaInitial volume (V₁): 350 mLInitial temperature (T₁): 308 KFinal pressure (P₂): ?Final volume (V₂): 425 mLFinal temperature (T₂): 333 K

Step 2: Calculate the final pressure of the air sample

If we assume an ideal gas behavior, we can calculate the final pressure of the air sample using the combined gas law.

P₁ × V₁/T₁ = P₂ × V₂/T₂

P₂ = P₁ × V₁ × T₂/T₁ × V₂

P₂ = 73 kPa × 350 mL × 333 K/308 K × 425 mL

P₂ = 65 kPa

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