The Synthesis Reaction of aluminum (Al) and iodine (I) forms a new, more complex product. What is the product?

Aluminum iodide (AlI₃)

Explanation:

The synthesis reaction of aluminum (Al) and iodine (I) can be illustrated as shown below:

Aluminium exhibit trivalent positive ion (Al³⁺)

Iodine exhibit univalent negative ion (I¯)

During reaction, there will be an exchange of ion as shown below:

Al³⁺ + I¯ —> AlI₃

Thus, we can write the balanced equation for the reaction as follow:

Al + I₂ —› AlI₃

There are 2 atoms of I on the left side and 3 atoms on the right side. It can be balance by putting 2 in front of AlI₃ and 3 in front of I₂ as shown below:

Al + 3I₂ —› 2AlI₃

There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by putting 2 in front of Al as shown below:

2Al + 3I₂ —› 2AlI₃

Thus the equation is balanced.

The product on the reaction is aluminum iodide (AlI₃)

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.

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