What is the angle between the carbon-hydrogen bond and one of the carbon-fluorine bonds in the fluoroform (

110.43 degrees

Explanation:

Fluoroform is CHF3. The molecule is expected to be tetrahedral  in shape.

Recall that any molecule with four electron domains and no lone pair on the central atom (AX4) is expected to be tetrahedral with a bond angle of 109.28 degrees.

This ideal bond angle of 109.28 degrees for tetrahedral molecules only obtains when all the atoms bonded to the central atom are the same. In the case of CHF3, the bond angles of the H-C-F bond(bond angle of 110.43 degrees) is different from that of the F-C-F bonds(bond angle of 108.50 degrees) because the bonding atoms (hydrogen and fluorine) have different electronegativities and all the bonds are not equivalent.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2