What total volume of ozone measured at a pressure of 24.5 mmHg and a temperature of 232 K can be destroyed when all of the chlorine from 15.5 g of CF3Cl goes through 10 cycles of these reactions

Explanation:

The breakdown reaction of ozone is as follows

It can be seen that 2 moles of ozone is required in the complete cycle

So for 10 cycles, 20 moles of ozone is required

m = Mass of = 15.5 g

M = Molar mass of = 104.46 g/mol

P = Pressure = 24.5 mmHg

T = Temperature = 232 K

R = Gas constant =

Number of moles is given by

From ideal gas law we have

For 20 cycles of the reaction the volume of the ozone is .

i would say b

explanation:

but i think i would need more information than that