Carbon monoxide and molecular oxygen react to form carbon dioxide. A 50.0 L reactor at 25.0 oC is charged with 1.00 bar of CO. The gas is then pressurized with O2 to give a total pressure of 3.52 bar. The reactor is sealed, heated to 350 oC to drive the reaction to completion, and cooled back to 25.0 oC. Compute the final partial pressure of each gas (in bar).

CO = zero

CO2 =1 bar

O2  = 2.02 bar

Explanation:

We are given

initial pressure of CO = 1bar

total pressure = 3.52 bar

so initial pressure of O2 = 3.52 - 1 = 2.52 bar

the reaction is

2CO + O2 →  2CO2

using the unitary method

2 moles of CO2 → 1 mole of O2

1  bar of CO → (required)

but we have more oxygen present , that means CO is the limiting reagent

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.

wher is the rest of the question