The heat of vaporization of water is 2,260 J. How much energy is released when 20 grams of steam is condensed at 100°C? *

45200J

Explanation:

Given parameters:

Heat of vaporization of water  = 2260J/g

Mass of steam = 20g

Temperature = 100°C

Unknown:

Energy released during the condensation  = ?

Solution:

This change is a phase change and there is no change in temperature

To find the amount of heat released;

          H  = mL

m is the mass

L is the latent heat of vaporization

 Insert the parameters and solve;

          H  = 20g x 2260J/g

           H = 45200J

b.final

the product of the pressure and volume is also constant