Barium sulfate is a contrast agent for X-ray scans that are most often associated with the gastrointestinal tract. Calculate the mass of that can dissolve in 340.0 mL of solution. The value for is .

3.07mg of BaSO₄ is the mass that can dissolve in 340.0mL of solution

Explanation:

The Ksp value of BaSO₄ is 1.5x10⁻⁹

The dissolution of BaSO₄ in water follows the equation:

BaSO₄(s) ⇄ Ba²⁺(aq) + SO₄²⁻(aq)

And ksp is defined as:

Ksp = 1.5x10⁻⁹ = [Ba²⁺] [SO₄²⁻]

As both Ba²⁺ and SO₄²⁻ ions comes from the same salt, the concentration of both ions = The maximum concentration that can be dissolved of BaSO₄ is X:

1.5x10⁻⁹ = [Ba²⁺] [SO₄²⁻]

1.5x10⁻⁹ = [X] [X]

1.5x10⁻⁹ = X²

X =

3.87x10⁻⁵M = [BaSO₄]

In 340mL = 0.340L, the moles of BaSO₄ are:

0.340L * (3.87x10⁻⁵ moles / L) = 1.317x10⁻⁵ moles of BaSO₄

To convert these moles to the mass in grams we need to use molar mass of BaSO₄ -233.38g/mol-:

1.317x10⁻⁵ moles of BaSO₄ * (233.38g / mol) = 3.07x10⁻³g =

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: