How much water is produced when 89m of H2 is reacted with 64gm of O2?

Mass of water produced = 801 g

Explanation:

Given data:

Mass of water produced = ?

Mass of H₂ = 89 g

Mass of oxygen = 64 g

Solution:

Chemical equation:

2H₂ + O₂      →      2H₂O

Number of moles of hydrogen:

Number of moles = mass/molar moles

Number of moles = 89 g/ 2 g/mol

Number of moles = 44.5 mol

Number of moles of oxygen:

Number of moles = mass/molar moles

Number of moles = 64 g/ 2 g/mol

Number of moles = 32 mol

Now we will compare the moles of water with oxygen and hydrogen.

                 H₂             :            H₂O

                  2              :              2

                  44.5         :            44.5

                 O₂             :             H₂O

                  1               :               2

               32               :              2/1×32 =64 mol

Number of moles of water produced by hydrogen are less thus it yield is limit by hydrogen.

Mass of water:

Mass = number of moles × molar mass

Mass = 44.5 mol ×  18 g/mol

Mass = 801 g

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