4 FeCO3 + O2 --> 2 Fe2O3 + 4CO2 a) A 35.0 g sample of pure FeCO3 produces 22.5 g of Fe2O3. What is the percentage yield of the reaction?

b) What mass of FeCO3 with a purity of 62.8% is needed to make 1.00 kg of Fe2O3?

The percentage yield of the reaction : 93.3%

Mass of FeCO₃ 2310.44 g

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction

4 FeCO₃ + O₂ ⇒ 2 Fe₂O₃ + 4CO₂

MW FeCO₃ : 115,854 g/mol

MW Fe₂O₃ : 159,69 g/mol

mol of 1 kg Fe₂O₃ = 1000 g

mol of FeCO₃

mass of FeCO₃

a purity of 62.8%