A sample of gas is placed into an enclosed cylinder and fitted with a movable piston. Calculate the work (in joules) done on the gas if it is compressed from 13.43 L to 6.87 L with a pressure of 1.91 atm.

Work done = 664.69 J

Explanation:

Given data:

Work done = ?

Initial volume = 13.43 L

Final volume = 6.87 L

Pressure = 1.91 atm

Solution:

work done = W = -PΔV

ΔV = V₂- V₁

work done = w = -P(V₂- V₁)

Now we will put the values in formula.

W = - 1 atm (6.87 L - 13.43 L)

W = - 1 atm (-6.56 L)

W = 6.56 atm.L

atm.L to joule:

6.56 atm.L × 101.325 J / 1L.atm

664.69 J

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.