Calculate the volume in ml of a 0.555 M NaHCO3 solution that contains 14.7 g of NaHCO3. ml

315 mL

General Formulas and Concepts:

Explanation:

Step 1: Define variables

0.555 M NaHCO₃

14.7 g NaHCO₃

Step 2: Define conversions

Molar Mass of Na - 22.99 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NaHCO₃ - [22.99 + 1.01 + 12.01 + 3(16.00)] g/mol = 84.01 g/mol

1 L = 1000 mL

Step 3: Find moles of solute

= 0.174979 mol NaHCO₃

Step 4: Find amount of solution

Step 5: Convert

= 315.278 mL

Step 6: Simplify

We are given 3 sig figs.

315.278 mL ≈ 315 mL

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