If 150 grams of water is to be heated from 15.0°C to 100°C to make a cup of tea, how much heat must be added? The specific heat of water is 4.18 J/g°C

53295 J or 53kJ

Explanation:

The specific heat of a substance is the amount of heat energy required to raise the temperature of a unit mass of a substance by one degree celsius.

The specific heat of water is 4.18 J/g°C. This means that to raise one gram of a sample of water by one degree celsius, 4.18 J of energy is required.

The heat energy (q), required to raise the temperature (ΔT) of a given substance, with a given mass (m) and specific heat capacity (c) is given by the formula;

q= m.c.ΔT

Substituting the data given into the formula, we will have,

q= 150g . 4.18 J/g°C . (100 - 15)°C

= 53295J

or 53kJ

-be a crystalline solid

- be soluble in water

-conduct electricity

hope this : )

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.