How many grams of NO2 would be formed from 1.0 mole of NO and excess of O2?

Mass = 46 g

Explanation:

Given data:

Number of moles of NO = 1.0 mol

Amount of O₂ = excess

Mass of NO₂ formed = ?

Solution:

Chemical equation:

2NO + O₂    →    2NO₂

Now we will compare the moles of No with NO₂.

                  NO           :           NO₂

                    2            :            2

                     1            :           1

Mass of NO₂ in gram:

Mass = number of moles × molar mass

Mass = 1 mol ×46 g/mol

Mass = 46 g

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

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