a reaction of 22.85 g of sodium hydroxide with 20.82 g of hydrogen chloride produces 10.29 g of water and X g of sodium chloride X = g

Mass of NaCl = 33.3 g

Explanation:

Given data:

Mass of NaOH = 22.85 g

Mass of HCl = 20.82 g

Mass of water produced = 10.29 g

Mass of NaCl = ?

Solution:

Chemical equation:

NaOH + HCl    →    NaCl + H₂O

Number of moles of NaOH:

Number of moles = mass/molar mass

Number of moles = 22.85 g/ 40 g/mol

Number of moles = 0.57 mol

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 20.82 g/ 36.5 g/mol

Number of moles = 0.57 mol

                        NaOH     :        NaCl

                           1           :          1

                       0.57        :       0.57

                      HCl          :            NaCl

                        1            :              1

                    0.57          :          0.57

Mass of NaCl:

Mass = number of moles × molar mass

Mass = 0.57mol × 58.44 g/mol

Mass = 33.3 g