When 11.0g of Mg(s) reacts with excess water to produce 5.75g of Mg(OH)2, what is the percent yield of the reaction

The chemical equation is given by :

From above equation :

24 gm Mg forms -----> 58 gm of

So, 11 g of Mg will form = .

Now, percentage yield is given by :

Therefore, the percentage yield is given by 21.63%.

Hence, this is the required solution.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.