Compute the bond energy of the C-Cl bond using the reaction and data in question 10, the value of the bond energy for the C-H bond of 410 kJ/mol and the value of the H-H bond of 432 kJ/mol. The C-Cl bond energy in kJ/mol is:

The bond formation of C-Cl bond by applying the given data in  question 10 is 325.4 kJ

Explanation:

From the data in question 10:

The equation for the given reaction can be expressed as:

The enthalpy of formation of the compounds  are as follows:

Substance                      

                              - 74.8

                                  120.9

                          -95.8

From the data obtained above, the enthalpy of the reaction can be computed as follows:

However; since we knew to be  -262.8  kJ

At standard conditions

Bond     Bond Energy (kJ/mol)

C-H        410

H-H        432

The bond energy can be calculated by using the expression:

Thus; the bond formation of C-Cl bond by applying the given data in  question 10 is 325.4 kJ

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.