Vitamin C was measured by an electrochemical method in a 50.0-mL sample of lemon juice. A detector signal of 2.02 mA was observed. A standard addition of 1.00 mL of 29.4 mM vitamin C increased the signal to 3.79 mA. Find the concentration (in mM units) of vitamin C in the juice.

The concentration (in mM units) of vitamin C in the juice is 0.64mM.

Explanation:

Let us calculate -:

Concentration of sample =>

                               = 29.4 mmol => 29.4mmol/50ml

                               = 0.588mM

plug in formula => or

= [2.02 micro-Amber/3.79micro-Amber]

plug in and simplify

1.81x = 1.17

x = 0.64mM

Hence , the answer is 0.64mM.

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