An 80 proof brandy is 40.0 % (v/v) ethyl alcohol. The "proof" is twice the percent concentration of alcohol in the beverage. How many milliliters of alcohol are present in 790 mL of brandy?

790 mL of an 80 proof brandy, which is 40.0 % (v/v) ethyl alcohol, contain 316 mL of ethyl alcohol.

An 80 proof brandy is 40.0 % (v/v) ethyl alcohol, that is, there are 40.0 mL of ethyl alcohol per 100 mL of brandy. This is the conversion factor.

We have 790 mL of brandy. This is the given information.

The milliliters of ethyl alcohol in 790 mL of brandy are:

790 mL of an 80 proof brandy, which is 40.0 % (v/v) ethyl alcohol, contain 316 mL of ethyl alcohol.

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Answer : The volume of water and alcohol present in 675 mL of this solution is 405 mL and 270 mL respectively.

Explanation :

As we are given that 40.0 % (v/v) alcohol solution. That means, 40.0 mL of alcohol present in 100 mL of solution.

Now we have to calculable the volume of alcohol in 675 mL solution.

As 100 mL of solution contains 40.0 mL of alcohol

So, 675 mL of solution contains alcohol

Thus, the volume of alcohol = 270 mL

Now we have to calculate the volume of water.

The volume of water = Volume of the solution - Volume of alcohol

Volume of water = 675 mL - 270 mL

The volume of water = 405 mL

Thus, the volume of water = 405 mL

Hence, the volume of water and alcohol present in 675 mL of this solution is 405 mL and 270 mL respectively.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

58750.08068 is the answer i think