Considering the following precipitation reaction: pb(no3)2(aq) + 2ki(aq) → pbi2(s) + 2kno3(aq),
which ion(s) would not be spectator ions?
a) pb2+ , no3-
b) k+ , i
c) no3- , pb2+
d) pb2+, i –
e) all the above ions are in the net ionic equation

The ions which are not spectator ions are and

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

The ions which are present on both the sides of the equation are and and are spectator ions.

Thus the net ionic equation is:

Hence, the correct answer is and

The net ionic equation of Pb(NO₃)₂(aq) and KI(aq) :

Pb²⁺(aq) +  2I⁻ (aq) ⇒ PbI₂(s) and

D) Pb²⁺, I – would not be spectator ions

The electrolyte in the solution produces ions.

The equation of a chemical reaction can be expressed in the equation of the ions

For strong electrolytes (the ionization rate = 1) is written in the form of separate ions, while the weak electrolyte (degree of ionization <1) is still written as an un-ionized molecule

In the ion equation, there is a spectator ion that is the ion which does not change (does not react) because it is present before and after the reaction

When these ions are removed, the ionic equation is called the net ionic equation

For gases and solids including water (H₂O) can be written as an ionized molecule

So only the dissolved compound is ionized ((expressed in symbol aq)

Reactions that occur:

Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq),

PbI₂(s) solid form that does not decompose in the form of ions

So the ionic equation becomes:

Pb²⁺(aq)+ 2NO₃⁻(aq) + 2K⁺ (aq) + 2I⁻ (aq) ⇒ PbI₂(s) + 2K⁺ + 2NO₃⁻

There is an ion spectator that is 2NO₃⁻ and  2K⁺ , so that if it is removed a net ionic equation will be formed:

Pb²⁺(aq) +  2I⁻ (aq) ⇒ PbI₂(s)

the net ionic equation

Keywords: the net ionic equation, an ion spectator