PLEASEEE SOS HELPPP An atom of lithium-6 has a mass of 6.01513 amu. The sum of the masses of this isotope's nucleons is 6.0497 amu. Calculate the binding energy in MeV. Remember 1 amu = 931.5 MeV. Enter your answer using three significant figures. ___ MeV

The binding energy  : 32.2 MeV

The binding energy : the energy to split the nucleus into individual protons and neutrons.

Can be formulated :

So, add the masses of subatomic particles of atom(proton+electron+neutron) and then substrac the mass of atom

Mass of subatomic particles :

For lithium-6 there are 3 protons, 3 electrons and 3 neutron

we can prove the sum of the masses of this isotope's nucleons of Lithium-6 above (which is 6.0497 amu.)

=3 x  1.008664 + 3 x 1.007276 + 3 x 0.00054858

=3.025995 + 3.021828+0.00164574=6.0495 amu(close to the value in the problem)

okay let's finish the question

The binding energy in MeV.

to 3 significant figure ⇒ 32.2 MeV

beta decay is the answer