Balance P4O10 + H2O → H3PO4

P4010 + 6H20 → 4H3PO4  

Explanation:

i rlly h8 this lesson but idt chem anymore but i used to do these alot for the last past 2 yrs

p-4     p-1

o-11    o-4

h-2     h-3

(these r for me so dont rlly mind it)

hope it helped tho:)))

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the answer is a and have a great day