Calculate the e. e. of a mixture containing 8.0 g of (-)-glyceraldehyde and 2.0 g of ( )-glyceraldehyde.

In stereochemistry, the enantiomeric excess (ee) of a substance is a measure of how pure it is. In this case, the impurity considered is the unwanted enantiomer: the mirror image of a chiral compound.

Which is 60% in this case

Explanation:

total mass of the mixture is = 10.09g

% of (-)-glyceraldehyde = 8.09/10.09 = 80%

by the same way, the % of ( )-glyceraldehyde is = 20%

the enantiomeric excess (e.e) are

e.e = %(-)-glyceraldehyde - %( )-glyceraldehyde

e.e = 80% - 20% = 60%

the millers tale is the answer.

i think it's c. i'm not sure but i think so.