What is the distance between two spheres, each with a charge of 2.4×10^-6 C, when the force between them in 0.50 N?

Use the formula F= k q1q2/r^2 where k= 1/4π€ and it's value in air is 9× 10^9.

q1=q2= 2.4×10^-6C

F= 0.5N

You will get the value of r^2 and then will have to find the squre root of that value.

Explanation:

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

answer seismograph;