Calculate the wavelength of the photon in nanometers. Show all of your work and units to receive full credit.

The question is incomplete, the complete question is;

An unknown element X absorbs a photon with an energy of 3.313 x 10-19).

a. Calculate the frequency of this photon. Show all of your work and units to receive full credit.

b. Calculate the wavelength of the photon in nanometers. Show all of your work and units to receive full credit.

a) 5 × 10^14 Hz

b) 5.98 × 10^-7 m

Explanation:

a)

Recall the formula;

E = hf

Where;

E= energy of the photon = 3.313 x 10-19 J

h= planks constant = 6.6 × 10^-34 Js

f= frequency of the photon (the unknown)

f= E/h = 3.313 x 10-19 J/6.6 × 10^-34 Js

f= 5 × 10^14 Hz

b)

From;

E= hc/λ

h= planks constant = 6.6 × 10^-34 Js

c= speed of light = 3 × 10^8 m/s

λ = wavelength of photon (the unknown)

λ= hc/E

λ = 6.6 × 10^-34 Js × 3 × 10^8 m/s/3.313 x 10-19 J

λ = 5.98 × 10^-7 m

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.