Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 10.1 g of methane is mixed with 58. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.

Explanation:

CH₄ + 2O₂ = CO₂ + 2H₂O

1 mole + 2 moles  = 1 moles + 2 moles

10.1 gm of methane = 10.1 / 16 = .63 moles of methane

58 g of oxygen = 58 / 32 = 1.8125 moles of oxygen

1 moles of methane reacts with 2 moles of oxygen to make 1 mole of CO₂

.63 moles of methane reacts with 1.26 moles of oxygen to make .63 mole of

CO₂

so CO₂ formed = .63 moles

.63 x 44 = 27.7 grams of CO₂

pv=nrt

explanation: