Solid phosphorusand chlorinegas react to form solid phosphorus pentachloride. Suppose you have of and of in a reactor. Calculate the largest amount of that could be produced. Round your answer to the nearest .

The largest amount of PCl₅ that can be produced from the reaction is 0.8 mole

We'll begin by determining the limiting reactant.

P₄ + 10Cl₂ —> 4PCl₅

1 : 10

9 : 2

From the above, Cl₂ is the limiting reactant as little amount is available for the reaction.

From the balanced equation above,

10 moles of Cl₂ reacted to produce 4 moles of PCl₅.

Therefore,

2 moles of Cl₂ will react to produce = (2 × 4)/10 = 0.8 mole of PCl₅.

Thus, the largest amount of PCl₅ produced from the reaction is 0.8 mole

Compete Question

Solid phosphorus and chlorine gas react to form solid phosphorus pentachloride. Suppose you have 9.0 mol of P and 2.0 of Cl2 in a reactor. Calculate the largest amount of PCl5 that could be produced. Round your answer to the nearest 0.1 mol.

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The question is incomplete, the complete question is;

Solid phosphorus and chlorine gas react to form solid phosphorus pentachloride. Suppose you have 9.0 mol of P and 2.0 of Cl2 in a reactor. Calculate the largest amount of PCl5 that could be produced. Round your answer to the nearest 0.1 mol.

0.8 mols

Explanation:

The equation of the reaction is:

P4(s)+10Cl2(g)→4PCl5(g)

We have to determine the limiting reactant by considering the reactant that yields the least number of moles of product.

1 mole of P yields 4 moles of PCl5

then 9.0 moles of P yields 9.0 * 4/ 1 = 36 moles of PCl5

Secondly;

10 moles of chlorine gas yields 4 moles of PCl5

2 moles of chlorine gas yields 2 *4/10 = 0.8 moles of PCl5

Since chlorine gas is the limiting reactant, the largest amount of PCl5 that can be produced in the reactor is 0.8 mols

the answer is 1260

you spend 7 hours in school for 1 school day with 5 school days in 1 school week with 36 school weeks in a school year.

7*5*36= 1260 it's all about multiplying