Solid phosphorusand chlorinegas react to form solid phosphorus pentachloride. Suppose you have of and of in a reactor. Calculate the largest amount of that could be produced. Round your answer to the nearest .

The largest amount of PCl₅ that can be produced from the reaction is 0.8 mole

We'll begin by determining the limiting reactant.

P₄ + 10Cl₂ —> 4PCl₅

1 : 10

9 : 2

From the above, Cl₂ is the limiting reactant as little amount is available for the reaction.

From the balanced equation above,

10 moles of Cl₂ reacted to produce 4 moles of PCl₅.

Therefore,

2 moles of Cl₂ will react to produce = (2 × 4)/10 = 0.8 mole of PCl₅.

Thus, the largest amount of PCl₅ produced from the reaction is 0.8 mole

Compete Question

Solid phosphorus and chlorine gas react to form solid phosphorus pentachloride. Suppose you have 9.0 mol of P and 2.0 of Cl2 in a reactor. Calculate the largest amount of PCl5 that could be produced. Round your answer to the nearest 0.1 mol.

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The question is incomplete, the complete question is;

Solid phosphorus and chlorine gas react to form solid phosphorus pentachloride. Suppose you have 9.0 mol of P and 2.0 of Cl2 in a reactor. Calculate the largest amount of PCl5 that could be produced. Round your answer to the nearest 0.1 mol.

0.8 mols

Explanation:

The equation of the reaction is:

P4(s)+10Cl2(g)→4PCl5(g)

We have to determine the limiting reactant by considering the reactant that yields the least number of moles of product.

1 mole of P yields 4 moles of PCl5

then 9.0 moles of P yields 9.0 * 4/ 1 = 36 moles of PCl5

Secondly;

10 moles of chlorine gas yields 4 moles of PCl5

2 moles of chlorine gas yields 2 *4/10 = 0.8 moles of PCl5

Since chlorine gas is the limiting reactant, the largest amount of PCl5 that can be produced in the reactor is 0.8 mols

the correct answer is boyle

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