Calculate the nuclear binding energy per nucleon for cobalt-59, the only stable isotope of cobalt. The mass of cobalt-59 is 58.933198 amu. (The mass of 11H is 1.00783 amu, and the mass of a neutron is 1.00866 amu.)

8.54 * 10^15 J

Explanation:

For Co-59

Protons- 27

Neutrons- 32

total calculated mass of protons = 27 * 1.00783 amu = 27.211 amu

total calculated mass of neutrons = 32 * 1.00866 amu =37.320 amu

Total calculated mass of nucleons = 27.211 amu + 37.320 amu = 64.531 amu

Mass defect = 64.531 amu - 58.933198 amu = 5.5978 amu

Binding energy = E=(Δm)c^2

Δm= mass defect

c=  speed of light

E=  5.5978 amu (3.0 *10^8)^2

E= 5.03 * 10^17 J

Binding energy per nucleon = Binding energy/ total number of nucleons

= 5.03 * 10^17 J/ 59 = 8.54 * 10^15 J

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8