A 10.0-g sheet of gold with a temperature of 18.0°C is laid flat on a sheet of iron that weighs 20.0 g and has a temperature of 55.6°C. Given that the specific heats of Au and Fe are 0.129 J g-1 0 c-1 and 0.444 J g-1 0 c-1, respectively, what is the final temperature of the combined metals? Assume that no heat is lost to the surroundings. (Hint: The heat gained by the gold must be equal to the heat lost by the iron.)

T = 50.83°C

Explanation:

Let the final temperature be T .

heat lost = mass x specific heat x fall in temperature

heat lost by iron = 20 x .444 x ( 55.6 - T )

heat gained  by gold  = 10 x .129 x ( T- 18 )

heat lost = heat gained

20 x .444 x ( 55.6 - T ) = 10 x .129 x ( T- 18 )

493.73 - 8.88 T = 1.29 T - 23.22

10.17 T = 516.95

T = 50.83°C

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