Calculate the equilibrium concentration of H3O in the solution if the initial concentration of C6H5COOH is 0.056 M . Express your answer using two significant figures.

1.9 × 10⁻³ M

Explanation:

Step 1: Write the acid ionization of benzoic acid

C₆H₅COOH(aq) + H₂O(l) ⇄ C₆H₅COO⁻(aq) + H₃O⁺(aq)

Step 2: Calculate the acid ionization constant (Ka) of benzoic acid

The pKa of benzoic acid is 4.20

pKa = -log Ka

Ka = antilog -pKa = antilog -4.20 = 6.31 × 10⁻⁵

Step 3: Calculate the equilibrium concentration of the hydronium ion

Considering that the initial concentration of the benzoic acid is Ca = 0.056 M, we can calculate the equilibrium concentration of the hydronium ion using the following expression.

[H₃O⁺] = √(Ca × Ka) = √(0.056 × 6.31 × 10⁻⁵) = 1.9 × 10⁻³ M

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a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.