Chemistry, 20.10.2020 20:01, oomale

0.90 g of hydrogen chloride (HCl) is dissolved in water to make 2.0 L of solution. What is the pH of the resulting hydrochloric acid solution

Answers: 1

Show answers

Answers

answered: pr47723

The pH of the resulting hydrochloric acid solution is 1.896

Explanation:

pH, short for Hydrogen Potential, is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH scale goes from 0 to 14. Values less than 7 indicate the range of acidity and those greater than 7 indicate alkalinity or basicity. The value 7 is considered neutral.

pH is defined as the opposite of the base 10 logarithm or the negative logarithm of the activity of hydrogen ions or hydronium ions (H₃O)., whose equation is

pH = -log [H⁺] = -log[H₃O⁺]

Then you must know the concentration of [H⁺] or [H₃O⁺]

A strong acid is one that dissociates completely, therefore, a quantity of H + ions are transferred to the solution. Since HCl is a strong acid, then [HCl] = [H⁺]

Being molarity the number of moles of solute that are dissolved in a certain volume, it is defined as:

$molarity=\frac{moles of solute}{volume}$

So you must know the number of moles of HCl. Being its molar mass equal to 36.45 $\frac{g}{mole}$ , then the following rule of three can be applied: if there are 35.45 grams of HCl in 1 mole, 0.9 grams of HCl in how many moles will they be?

$moles of HCl=\frac{0.9 grams*1 mole}{35.45 grams}$

moles of HCl= 0.0254

Then, being the number of moles of solute 0.0254 and the volume 2 L, the molarity is:

$molarity=\frac{0.0254 moles}{2 L}$

$molarity=0.0127\frac{moles}{L}$

Then, the concentration of [HCl] is 0.0127 $\frac{moles}{L}$ . So [HCl] = [H⁺] = 0.0127 $\frac{moles}{L}$ .

So the pH is calculated as:

pH = -log [H⁺]= -log 0.0127

pH= 1.896

The pH of the resulting hydrochloric acid solution is 1.896

answered: Guest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.