The equilibrium constant for the chemical equation N2(g)+3H2(g)↽−−⇀2NH3(g) is Kp=0.0133 at 181 ∘C. Calculate the value of Kc for the reaction at 181 ∘C.

Kc is 18.478

Explanation:

Here we want to calculate Kc given Kp

The equation that links both is given as follows;

Kc = Kp/(RT)^Δn

where Kp = 0.0133

R is molar gas constant = 0.0821 L.atm/mol.k

T is temperature in kelvin = 181 + 273 = 454K

Δn is the change in number of moles between products and reactants = 2-4 = -2

Substituting these values, we have;

Kc = 0.0133/(0.0821 * 454)^-2

Kc = 18.478

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.