If 550 grams of KClO3 breaks down and produces 175 grams of KCl, how many grams of O2 are produced?

215.51 g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

Next, we shall determine the mass of KClO3 that decomposed and the mass of O2 produced from the balanced equation. This is illustrated below:

Molar mass of KClO3 = 39 + 35.5 + (16×3)

= 39 + 35.5 + 48

= 122.5 g/mol

Mass of KClO3 from the balanced equation = 2 × 122.5 = 245 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 3 × 32 = 96 g

From the balanced equation above,

245 g of KClO3 decomposed to produce 96 g of O2.

Finally, we shall determine the mass of O2 produced by the decomposition of 550 g of KClO3. This can be obtained as follow:

From the balanced equation above,

245 g of KClO3 decomposed to produce 96 g of O2.

Therefore, 550 g of KClO3 will decompose to produce =

(550 × 96)/245 = 215.51 g of O2.

Therefore, 215.51 g of O2 were obtained from the reaction.

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