Element Y has two naturally occurring isotopes. The most dominant isotope has a mass of 114.3789 amu and a percent abundance of 64.23%. What is the mass of the second isoptope if the average atomic mass is 128.4359 amu? Remember that the two percentages will have to sum to 100%.
Answer to the correct number of sigtigs including units in your answer.
(to receive full credit, work must be submitted for this question)

153.6771 amu

Explanation:

From the question given above, the following data were:

Isotope A:

Mass of A = 114.3789 amu

Abundance (A%) = 64.23%

Isotope B:

Mass of B =.?

Abundance (B%) = 100 – A%

Abundance (B%) = 100 – 64.23

Abundance (B%) = 35.77%

average atomic mass of Element Y = 128.4359 amu

The mass of the 2nd isotope (i.e isotope B) can be obtained as follow:

Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

128.4359 = [(114.3789 × 64.23)/100] + [(Mass of B × 35.77) /100]

128.4359 = 73.4656 + (Mass of B × 0.3577)

Collect like terms

128.4359 – 73.4656 = Mass of B × 0.3577

54.9703 = Mass of B × 0.3577

Divide both side by 0.3577

Mass of B = 54.9703 / 0.3577

Mass of B = 153.6771 amu

Therefore, the mass of the 2nd isotope is 153.6771 amu

a boiling water reactor does not boil the water. a pressurized water reactor boils the water faster. a pressurized water reactor is heated directly by the core. a pressurized water reactor does not use fission.

plasma is the state of matter where the substance is ionized and has no definite shape or volume. the fact of being ionized makes the substance a good electrical conductor.