If you know the volume and the density of an iron rod, how would you calculate the mass of that iron rod? Show a formula.

for an example

volume can easily be calculated: pi*(d^2/4)*length -> pi*[(7x10^-2)/4]*70x10–2 = volume of iron rod {VOIR}

Density = mass / volume

Therefore

Mass = density x volume

However, weight is equals to ‘mass x g (free fall acceleration’

So mass is in kg but weight is a force so simple force equation to where ‘a (acceleration)’ in ‘F=ma’ is ‘g’.

Hence,

Weight = 9.81 ms^-2 (is ‘g’) x 7870 kgm^-3 x VOIR m^3 is *insert calculated answer* N.

Explanation:

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.