Calculate the numerical Kc value for the following reaction if the equilibrium mixture contains 0.51 M CO2 , 0.30 M H2 , 1.8 M CH4 , and 2.0 M H2O. CO(g) + 3H2 (g) ⇌ CH4 (g) + H2O (g)

Most smaller stars don't have a radiative zone.

I'm sorry but i'm only grade

C, small, hard spheres with insignificant volumes

Answer is: hydrogen is being oxidized.chemical reaction: co₂ + h₂ → co + h₂o.oxidation half reaction: h₂ → 2h⁺ + 2e⁻.reduction half reaction: c⁺⁴ + 2e⁻ → c⁺².oxidation is increase of oxidation number, hydrogen change oxidation number from neutral charge (in molecule of hydrogen) to oxidation number +1 (in water).