An unknown metal cation (alias, M) contains 26 total electrons. It forms an ionic compound with sulfide with the formula MS. What is the symbol of the cation?
*When writing the cation, write the symbol, put in 1 space, then the charge.
Example: Fe2+ would be written Fe 2+

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o