A mixture of xenon and oxygen gas is compressed from a volume of to a volume of , while the pressure is held constant at . Calculate the work done on the gas mixture. Round your answer to significant digits, and be sure it has the correct sign (positive or negative).

Explanation:

Hello,

In this case, since the work at constant pressure is computed via:

For an initial volume of 99.0 L and a final one of 98.0 L, accounting for a compression process at a pressure of 69.0 atm, we obtain a negative work, meaning that work is done on the gas, according to the first law of thermodynamics:

However, the work in kJ with three significant figures because the initial data have all three significant figures, is:

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answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol