Calculate the enthalpy change to raise the temperature of 180.0 g of water from 10.0°C to 40.0°C. The molar heat capacity for water is 75.3 J/Kmol. a. What values have you been given? b. What value are you trying to find? c. Which heat equation do you need? d. Now solve the problem.

22572J

Explanation:

a) The following values have been given:

Mass of water = 180.0g

Initial temperature = 10°C

Final temperature = 40°C

molar heat capacity for water = 75.3J/Kmol

To calculate the specific heat capacity of water (c), we divide the molar heat capacity by molar mass of water (18g/mol)

That is; 75.3/18

= 4.183 Jg/K

b) The enthalpy change denoted by ∆H is the value we are trying to find.

c) To find enthalpy change (∆H), we use the formula:

∆H = m × c × ∆T

Where; m= mass

c= specific heat capacity

∆T= change in temperature =

(final temp - initial temp)

∆H = m × c × ∆T

∆H = 180 × 4.18 × (40-10)

∆H = 180 × 4.18 × 30

∆H = 22572J

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chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.