Normally the capital ÎGo° for a reaction would be determined at standard temperature with each reactant at a concentration of 1 M. Letâs assume that the 1 M 2-PG solution will reach the same equilibrium ratio that would be observed under standard conditions. The enzyme enolase catalyzes the conversion of 2-PG to phosphoenolpyruvate (PEP) in living systems. You find that when you add enolase to your 2-PG solution it reaches an equilibrium with 0.68M PEP and 0.32 M 2-PG. What is the capital ÎGo° for this reaction? Use R= 1.987 cal/mol. K

a. +559 cal/mol
b. - 559 cal/mol
c. +379 cal/mol
d.-379 cal/mol

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰   =  -  RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰   =   - 1.987 x 273 x  ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.