The rate of reaction in terms of the "rate law expression" includes the rate constant (kk), the concentration of the reactants, and the orders of the reaction with respect to the different reactants. Consider the following reaction: A+B→C+DA+B→C+D The initial concentrations of the reactants AA and BB are 0.200 MM and 0.350 MM, respectively. The rate of reaction is 0.060 M⋅s−1M⋅s−1, and the orders of the reaction, with respect to reactants AA and BB, are 1 and 2, respectively. Determine the rate constant (kk) for the reaction using the rate law. Express your answer in M−2⋅s−1M−2⋅s−1 to three significant figures.

Explanation:

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In this case, considering the given specific orders of reaction, we can write the rate law as:

Thus, considering the concentrations of A and B to be 0.200 M and 0.350 M respectively and a rate of 0.060 M/s, the rate constant turns out:

This is what we know as a third-order reaction since the specific orders both add to 3.

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you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6