A 9.0 g of a mysterious substance was heated from 23.0°C to 85.0°C using 127 J of heat. To identify the substance we need to know the specific heat capacity of it. What is the mysterious substance’s specific heat capacity?

0.228 J/g°C

Explanation:

The specific heat capacity, denoted by c, can be calculated using the formula:

Q = m × c × ∆T

Where; Q = amount of heat

m = mass

c = specific heat capacity

∆T = change in temperature

In this question, m = 9.0g, Q = 127J, T1 = 23°C, T2 = 85°C

Using, Q = m × c × ∆T

127 = 9 × c × (85-23)

127 = 9 × c × 62

127 = 558c

c = 127/558

c = 0.2275

c = 0.228 J/g°C

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