Calculate the mass (g) of 1.5 moles of Sulfur.

48 g S

Explanation:

Step 1: Define

Molar Mass of Sulfur (S) - 32.07 g/mol

Step 2: Use Dimensional Analysis

= 48.105 g S

Step 3: Simplify

We have 2 sig figs.

48.105 g S ≈ 48 g S

the role of the microscope world in creating new materials .

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g